25 Spring 439/639 TSA: Lecture 7

Author

Dr Sergey Kushnarev

1 More on ARMA(\(1,1\))

1.1 ACVF of ARMA(\(1,1\))

Recall last time, for the ARMA(\(1,1\)) \[ Y_t - \phi Y_{t-1} = e_t - \theta e_{t-1}, \] we derived a causal GLP (also an MA(\(\infty\))) representation for \((Y_t)\) \[ Y_t = e_t + \sum_{k=1}^{\infty} \phi^{k-1} (\phi - \theta) e_{t-k} \] whenever the ARMA(\(1,1\)) is causal (only if \(|\phi|<1\)). We will use the GLP representation above to find the ACVFs for \((Y_t)\) through the Yule-Walker method.

For \(k\ge 0\), multiply \(Y_{t-k}\) on both sides and take the expectations. \[ \begin{split} Y_t - \phi Y_{t-1} &= e_t - \theta e_{t-1},\\ Y_t Y_{t-k} - \phi Y_{t-1} Y_{t-k} &= e_t Y_{t-k} - \theta e_{t-1} Y_{t-k}, \\ \mathbb{E}[Y_t Y_{t-k}] - \phi \mathbb{E}[Y_{t-1} Y_{t-k}] &= \mathbb{E}[e_t Y_{t-k}] - \theta \mathbb{E}[e_{t-1} Y_{t-k}] . \end{split} \] As before, since \((Y_n)\) is mean zero and stationary, \(\mathbb{E}[Y_{t} Y_{t-k}] = \gamma_{k}\) and \(\mathbb{E}[Y_{t-1} Y_{t-k}] = \gamma_{k-1}\). So the \(k\)-th YW equation is \[ \gamma_{k} - \phi \gamma_{k-1}= \mathbb{E}[e_t Y_{t-k}] - \theta \mathbb{E}[e_{t-1} Y_{t-k}]. \] Assuming causality, we can use the previous causal GLP, then \[ \gamma_{k} - \phi \gamma_{k-1}= \mathbb{E}[e_t (e_{t-k}+ \psi_1 e_{t-k-1 + \cdots})] - \theta \mathbb{E}[e_{t-1} (e_{t-k}+ \psi_1 e_{t-k-1 + \cdots})]. \] Consider all possible \(k\ge 0\): \[ \begin{cases} \gamma_{0} - \phi \gamma_{1} = \sigma_e^2 - \theta \psi_1 \sigma_e^2, &0\text{th YW eq}\\ \gamma_{1} - \phi \gamma_{0} = 0 - \theta \sigma_e^2, &1\text{st YW eq}\\ \gamma_{k} - \phi \gamma_{k-1}= 0 - \theta 0 = 0, &k\text{-th YW eq, for } k\ge 2 \end{cases} \] Recall that \(\psi_1 = \phi-\theta\), from the first 2 YW equations we have \[ \begin{cases} \gamma_{0} - \phi \gamma_{1} = \sigma_e^2 - \theta (\phi-\theta) \sigma_e^2 \quad &(\text{YW}0)\\ \gamma_{1} - \phi \gamma_{0} = - \theta \sigma_e^2 &(\text{YW}1) \end{cases} \] \((\text{YW}0) + \phi(\text{YW}1)\): \[ (1 - \phi^2)\gamma_0 = (1 - 2\theta\phi + \theta^2)\sigma_e^2 \implies \gamma_0 = \frac{1 - 2\theta\phi + \theta^2}{1 - \phi^2}\sigma_e^2 . \] Then plug it into \((\text{YW}1)\): \[ \begin{split} \gamma_1 &= \phi\gamma_0 - \theta\sigma_e^2 = \sigma_e^2 \left( \frac{\phi(1-2\theta\phi+\theta^2)}{1-\phi^2} - \frac{\theta (1-\phi^2)}{1-\phi^2} \right) \\ &= \sigma_e^2 \left( \frac{\phi - 2\theta\phi^2 + \phi\theta^2 - \theta + \theta\phi^2} {1-\phi^2} \right) \\ &= \sigma_e^2 \frac{\phi - \theta + \theta\phi(\theta-\phi)}{1-\phi^2} = \sigma_e^2 \frac{(\phi-\theta)(1-\theta\phi)}{1-\phi^2} . \end{split} \] Use the \(k\)-th YW equations (for \(k\ge 2\)) recursively: \[ \gamma_k = \phi^{k-1} \frac{(\phi - \theta)(1 - \theta\phi)}{1 - \phi^2} \sigma_e^2, \quad \forall k\ge 1. \] We can observe that, \(\gamma_k \to 0\) exponentially as \(k\to \infty\) (since \(|\phi|<1\) under causality condition).

1.2 Invertible representation for ARMA(\(1,1\))

By the invertiblity condition (see last lecture), we need all the roots of MA polynomial are outside the unit disk, which reduces to \(|\theta| <1\) for ARMA(\(1,1\)). When invertibility holds, we have the following invertible representation (also an AR(\(\infty\))) for ARMA(\(1,1\)): \[ e_t = Y_t + \sum_{j=1}^{\infty} \theta^{j-1} (\theta - \phi) Y_{t-j} . \] Exercise: derive the formula above, and verify \(\sum_{j=0}^{\infty} |\pi_j| < \infty\) in this invertible representation.

2 General ARMA(\(p,q\))

2.1 Find the causal GLP representation

Consider the ARMA(\(p,q\)) \[ Y_t - \phi_1 Y_{t-1} - \cdots - \phi_p Y_{t-p} = e_t - \theta_1 e_{t-1} - \cdots - \theta_q e_{t-q} . \] Assume the causality condition holds, i.e., assume all the roots of the AR polynomial are outside of the unit disk. So there exists a causal GLP representation \(Y_t = \sum_{j=0}^{\infty} \psi_j e_{t-j}\). Our goal is to find \(\{\psi_j\}\).

We can simply plug it into the ARMA(\(p,q\)) equation \[ \begin{split} &\left( \psi_0 e_t + \psi_1 e_{t-1} + \psi_2 e_{t-2} + \cdots \right) - \phi_1 \left( \psi_0 e_{t-1} + \psi_1 e_{t-2} + \psi_2 e_{t-3} + \cdots \right) - \cdots - \phi_p \left( \psi_0 e_{t-p} + \psi_1 e_{t-p-1} + \psi_2 e_{t-p-2} + \cdots \right) \\ &= e_t - \theta_1 e_{t-1} - \theta_2 e_{t-2} - \cdots - \theta_q e_{t-q} . \end{split} \] Then compare the coefficients for \(e_{t-k}\) on both sides: \[ \begin{cases} \psi_0 = 1 \\ \psi_1 - \phi_1 \psi_0 = -\theta_1 \\ \psi_2 - \phi_1 \psi_1 - \phi_2 \psi_0 = -\theta_2 \\ \psi_3 - \phi_1 \psi_2 - \phi_2 \psi_1 - \phi_3 \psi_0 = -\theta_3 \\ \quad \cdots \\ \psi_j - \phi_1 \psi_{j-1} - \phi_2 \psi_{j-2} - \cdots - \phi_p \psi_{j-p} = 0, \text{ for large } j \text{ such that } j\ge p \text{ and } j>q \end{cases} \] So we get \[ \begin{cases} \psi_0 = 1 \\ \psi_1 = \phi_1 - \theta_1 \\ \psi_2 = \phi_1 \psi_1 + \phi_2 - \theta_2 \\ \psi_3 = \phi_1 \psi_2 + \phi_2 \psi_1 + \phi_3 - \theta_3 \\ \quad\cdots \\ \psi_j = \phi_1 \psi_{j-1} + \phi_2 \psi_{j-2} + \cdots + \phi_p \psi_{j-p}, \text{ for large } j \text{ such that } j\ge p \text{ and } j>q \end{cases} \] which can be seen as recursive equations for \(\{\psi_j\}\).

2.2 YW approach for ACVF

The basic idea of YW method is same as before, assume causality and stationarity. For any \(k>q\), the \(k\)-th YW equations is \[ \begin{split} \mathbb{E}[Y_t Y_{t-k}] - \phi_1 \mathbb{E}[Y_{t-1} Y_{t-k}] - \cdots - \phi_p \mathbb{E}[Y_{t-p} Y_{t-k}] &= \mathbb{E}[e_t Y_{t-k}] - \theta_1 \mathbb{E}[e_{t-1} Y_{t-k}] - \cdots - \theta_q \mathbb{E}[e_{t-q} Y_{t-k}] \\ \gamma_{k} - \phi_1 \gamma_{k-1} - \cdots - \phi_p \gamma_{k-p} &= 0, \quad \forall k>q \end{split} \] So the recursion part of YW equations have the structure as \(AR(p)\). Using the earlier results, suppose the \(p\) roots (assuming \(\phi_p \ne 0\)) of the AR polynomial are \(z_1,...,z_p\) and they are all distinct, then there exist \(p\) complex numbers \(A_1,...,A_p\) such that \[ \gamma_k = A_1 z_1^{-k} + A_2 z_2^{-k} + \cdots + A_p z_p^{-k} \] hold for all \(k \ge q+1-p\).

  • If \(p\ge q\): we need to solve \((\gamma_0,...,\gamma_p)\) from the first \(p+1\) YW equations (YW eq\(0\), …, YW eq\(p\)), then we can use \((\gamma_{1},...,\gamma_{p})\) as the initial conditions to determine \((A_1,...,A_p)\).
  • If \(q> p\): we need to solve \((\gamma_0,...,\gamma_q)\) from the first \(q+1\) YW equations (YW eq\(0\), …, YW eq\(q\)), then use \((\gamma_{q-p+1},...,\gamma_{q})\) as the initial conditions to determine \((A_1,...,A_p)\).

Remark: dividing the YW equation by \(\gamma_0\) gives \(\rho_{k} - \phi_1 \rho_{k-1} - \cdots - \phi_p \rho_{k-p} = 0\) for \(k>q\). So the ACF has the same structure \(\rho_k = \widetilde{A}_1 z_1^{-k} + \widetilde{A}_2 z_2^{-k} + \cdots + \widetilde{A}_p z_p^{-k}\).

Remark: if the \(p\) roots are not distinct, ACVF/ACF have more complicated formula as we discussed before (see last lecture).

3 A brief summary so far

Process Causal Invertible (weakly) Stationary ACF behavior
MA(1) Always. \(|\theta| < 1\). Always. \(\rho_1 \in [-0.5, 0.5]\), and \(\rho_k=0\) for \(k\geq2\).
MA(q) Always. Roots of MA-poly outside of unit disk. Always. \(\rho_k=0\) for \(k>q\).
AR(1) \(|\phi| < 1\). Always. \(|\phi| \neq 1\). \(\rho_k = \phi^k\), exponential decay.
AR(p) Exercise Exercise Exercise Exercise
ARMA(1,1) \(|\phi| < 1\). \(|\theta| < 1\). \(|\phi| \neq 1\). Exponential decay.
ARMA(p,q) Exercise Exercise Exercise Exercise